Math, asked by kalaivanijain007, 5 months ago

Find any two solutions for the following equation: 3x + 4y = 7. Also mention how

many solutions are there for this equation.​

Answers

Answered by shatakshigairola941
1

Answer:

Solution:

Solution:(i) 3x + 4y =7 ….(1)

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3x

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find Solutions

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1Thus x = 1 and y = 1 is the solution of 3x + 4y = 7

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1Thus x = 1 and y = 1 is the solution of 3x + 4y = 7Again, Substituting x = 2 in (2)

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1Thus x = 1 and y = 1 is the solution of 3x + 4y = 7Again, Substituting x = 2 in (2)y = 1/4 x (7 – 3 x 2) = 1/4 x 1 = 1/4

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1Thus x = 1 and y = 1 is the solution of 3x + 4y = 7Again, Substituting x = 2 in (2)y = 1/4 x (7 – 3 x 2) = 1/4 x 1 = 1/4Thus x = 2 and y = 1/4 is the solution of 3x + 4y = 7

Solution:(i) 3x + 4y =7 ….(1)Step 1: Isolate above equation in y.Subtract 3x from both the sides,3x + 4y – 3x = 7 – 3x4y = 7 – 3xDivide each side by 4y = 1/4 x (7 – 3x) ….(2)Step 2: Find SolutionsSubstituting x = 1 in (2)y = 1/4 x (7 – 3) = 1/4 x 4 = 1Thus x = 1 and y = 1 is the solution of 3x + 4y = 7Again, Substituting x = 2 in (2)y = 1/4 x (7 – 3 x 2) = 1/4 x 1 = 1/4Thus x = 2 and y = 1/4 is the solution of 3x + 4y = 7Therefore, (1, 1) and (2, 1/4) are two solution of 3x + 4y = 7.

Answered by ashokkumar7869
1

Answer:

7xy=7

xy=7/7

=1

Step-by-step explanation:

This is the answer of your question

Similar questions