find AP 84,80,76,72 find t12
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Answered by
0
Answer:
heya mate there's your answer
Given series 84,80,76........is in AP
let first term of the AP be t1 =84
second term of the AP be t2=80
and common difference of the AP be d
d=t2-t1
d=80-84
d=-4
so common difference of the AP is d =-4
we know that nth term of an AP is,
tn=t1+(n-1)d
t12=t1+(12-1)d
=84+(11)(-4)
=84-44
=40
so t12=40
hope it helps you..........
Thank you!!!
Answered by
1
Answer:
40
Step-by-step explanation:
a=84
d=-4
n=12
an=a+(n-1)d
a12=84+(12-1)-4
=84+11(-4)
=84+-44
=40
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