Math, asked by santoshthopate63, 1 year ago

find AP 84,80,76,72 find t12​

Answers

Answered by manasa1010
0

Answer:

heya mate there's your answer

Given series 84,80,76........is in AP

let first term of the AP be t1 =84

second term of the AP be t2=80

and common difference of the AP be d

d=t2-t1

d=80-84

d=-4

so common difference of the AP is d =-4

we know that nth term of an AP is,

tn=t1+(n-1)d

t12=t1+(12-1)d

=84+(11)(-4)

=84-44

=40

so t12=40

hope it helps you..........

Thank you!!!

Answered by dharanahimaani
1

Answer:

40

Step-by-step explanation:

a=84

d=-4

n=12

an=a+(n-1)d

a12=84+(12-1)-4

    =84+11(-4)

    =84+-44

    =40

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