Question

find AP whose 3rd term is 16 and 7th term is more than the 5th term by 12​

Answer 1

Answer:

             a = 4

Step-by-step explanation:

Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7th term

a3 = 16

a7 = a5 + 12  ............ (1)

Let the common difference be "d"

Common difference is equal in AP  

So,

a7 = a5 + d + d = a5 + 2d ............(2)

From Equation (1) & (2)

a5 + 12 = a5 + 2d  

2d = 12

d = 6

From Given, we get that

a3 = 16

a3 = a + 2d = 16

a + ( 2 × 6 ) = 16              [ We know that d = 6 ]

a + 12 = 16

a = 4

So first term is 4 .... We can find AP by adding d continuously

So, AP is 4, 10, 16, 22, 28.......  

Hope it helps !!!

Answer 2

Answer:

28,22,16,10,6.......

Step-by-step explanation:

By doing we will get common difference d=-6 and a=28 we know that in AP series the numbers will be in the order a,a+d,a+2d,a+3d..........