find AP whose 3rd term is 16 and the 7 term exceeds the 5th term by 12
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Answer:4,10,16....
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given,
a3=16
a7-a5=12
to find AP
solution,
a3=a+2d
16=a+2d
a=16-2d--------(1)
a7-a5=12
a+6d-a-4d=12
2d=12
d=6
a=16-2(6). from (1)
a=4
the AP is 4,10,16,...
I hope that this would help you...
a3=16
a7-a5=12
to find AP
solution,
a3=a+2d
16=a+2d
a=16-2d--------(1)
a7-a5=12
a+6d-a-4d=12
2d=12
d=6
a=16-2(6). from (1)
a=4
the AP is 4,10,16,...
I hope that this would help you...
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