Question

Find ap whose third term is 16 and seventh term exceeds the 5th term by 12

Answer 1

HEYA!!!!

Here is your answer :

__________________________

Given,

7th term exceeds 5th term by 12

a + 6d = a + 4d + 12

6d - 4d = 12

2d = 12

d = 6,,

From,

3rd term = 16

a + 2d = 16

a + 2 (6) = 16

a + 12 = 16

a = 4

Therefore,

AP = 4 , 10 ,16...

Answer 2

ANSWER

⇒ The third term = a3 = a+2d = 16.........(i)

and seventh term = a7 - a + 6d

Given that a7 - a5 = 12

⇒ (a+6d) - (a+4d) = 12

⇒ a+6d - a - 4d = 12

⇒2d = 12

⇒ d = 6

substituting the value of d = 6 in (i)

a + 12 = 6

a = 4

∴ The first term of the A.P. is 4 and the common difference is 6.

∴ The A.P. is 4,10,16,22,28,34,.....

HOPE IT HELPS

THANKS