Question

Find are of isosceles triangle whose base is 4cm and length of equal sides is 6cm

Answer 1

${2}^{2} + {3}^{2} = 4 + 9 = \sqrt{13} \: \:area \: of \: triangle \: is \: 1 \div 2 \times 4 \times \sqrt{13 } \: = \: 2 \sqrt{13}$