Question

Find area (in cm²) of

i) ∆DRC
ii) ∆BQC
iii) whole figure (total area)

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Answer 1

Here is the answer!

□DABC Is a Rectangle

Therefore, DA=6,AB=8

In,Triangle APB

Draw PY line such it's perpendicular to AB

AY=1/2AB

=4cm

AY=1/2AP (converse of 30-60-90 theorem)

4=1/2AP

4×2=AP

=8

This can be done to all sides of the triangle

Triangle APB=Triangle DRC

Triangle DAS=Triangle CBQ

(Using Pythagoras Theorem to find the heights)

Triangle APB=Triangle DRC=2root3

Triangle DAS=Triangle CBQ=3root3

Area of Triangle APB= bh/2

8×2root3/2= 13.856

Triangle DAS=Triangle CBQ

=6×3root3/2= 15.588

Area of rectangle=l×b

8×6=48

Total Area = 77.444

Final answer:- ∆DRC=13.856

∆BQC= 15.588

Total Area=7.444

Hope it helped

Answer 2

This is the right answer of your question