Question

find area of a cuboid with length 10.5cm, breadth 6.5 cm and height 2.5 cm​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore T.S.A\:of\:cuboid=221.5\:{cm}^{2}}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Length = 10.5 \: cm \\ \\ \implies Breadth = 6.5 \: cm \\ \\ \implies Height = 2.5 \: cm \\ \\ \underline \bold{To \: Find : } \\ \implies T.S.A \: of \: cuboid = ?$

•. According to given question :

$\bold{Using \: formula \: of \: T.S.A \: of \: cuboid : }\\ \implies T.S.A \: of \: cuboid = 2(lb + bh + hl) \\ \\ \implies T.S.A = 2(10.5 \times 6.5 + 6.5 \times 2.5 + 2.5 \times 10.5) \\ \\ \implies T.S.A= 2(68.25 + 16.25 + 26.25) \\ \\ \implies T.S.A = 2 \times 110.75 \\ \\ \bold{\implies T.S.A= 221.5 \: {cm}^{2} }$

Answer 2

Step-by-step explanation:

Total surface area of cuboid

$= 2(lb + bh + hl) \\ = 2(10.5 \times 6.5 + 6.5 \times 2.5 + 2.5 \times 10.5)$

$= 2 \times 110.75$

=221. 5

Therefore,

area of a cuboid is 221.5 cm sq