Question

Find area of a parallelogram whose base is 8 cm and height 4 cm​

Answer 1

Answer:

32 square cm

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Question :-

• Find the area of parallelogram whose base is 8 cm and height is 4 cm.

To Find :-

• Area of parallelogram.

Solution :-

Given :

• Base = 8 cm
• Height = 4 cm

By using the formula,

${\longrightarrow{\sf Area\ of\ parallelogram\ =\ b \times h}}$

Where,

• b = base of the parallelogram
• h = height of the parallelogram

According to the question, by using the formula, we get :

${\longrightarrow{\sf Area\ of\ parallelogram\ =\ b \times h}}$

${\longrightarrow{\sf 8 \times 4}}$

${\longrightarrow{\sf 32\ cm^2}}$

∴ Hence, area of parallelogram is 32 cm².

More To Know :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$