Question

Find area of a quadrilateral ABCD in which ab=3cm bc=4cm cd=4cm da=5cm and ac=5cm.

Answer 1

Answer:

Step-by-step explanation:

For ΔABC

a = 4 cm

b = 5 cm

c = 3 cm

∵ a2 + c2 = b2

∴ ΔABC is right angled with ∠B = 90°.

∴ Area of right triangle ABC

equals 1 half cross times space Base space cross times space Height

equals space 1 half cross times 3 cross times 4 equals 6 space cm squared

For ΔACD

a = 4 cm b = 5 cm

c = 5 cm

∴ Area of the ΔACD

= 2 x 4.6 cm2 (approx.)

= 9.2 cm2 (approx.)

∴ Area of the quadrilateral ABCD

= Area of ΔABC + Area of ΔACD

= 6 cm2 + 9.2 cm2

= 15.2 cm2, (approx.)

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