Question

Find area of a regular hexagon whose one side is 17 cm and it's height is 33 cm

Answer 1

Area of a regular hexagon is 750.84 cm².

Step-by-step explanation:

Given : A regular hexagon whose one side is 17 cm and it's height is 33 cm.

To find : The area of a regular hexagon ?

Solution :

The area of a regular hexagon is given by,

$A= \dfrac{3\sqrt{3}}{2} a^{2}$

Here, side of the regular hexagon is a=17 cm.

Substitute the value,

$A= \dfrac{3\sqrt{3}}{2}\times (17)^{2}$

$A= \dfrac{3\sqrt{3}}{2} \times 289$

$A= 750.84\ cm^2$

Therefore, area of a regular hexagon is 750.84 cm².

#Learn more

ABCDEF is a regular hexagon with side is 6cm. find the area of regular hexagon

https://brainly.in/question/8010256

Answer 2

Answer:

Area of regular hexagon=750

Step-by-step explanation:

(H)² = (P)² + (B)²

(17×17 ) = (P)² + (8×8)

289 =(P)² + 64

(P)² = 289-64

(P)² = 225

P= 15cm

Area of Trapezium= ½ × H × ( Parallel 1+Parallel 2)

= ½×15×(33+17)

=½×15cm × 50cm

=15cm×25cm

= 375cm²

Area of Trapezium=½×H×(P1 +P2)

=½×15 cm ×(17cm+33cm)

=½×15cm×50cm

=15×25

=375cm²

Area of polygon=375cm²+375cm²

=700cm² ANS.

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