Question

find area of a rhombus one side of which measures 20cm and one of whose diagonals is 24cm.

Answer 1

Side of rhombus = 20 cm

D1 = 24 cm

Side of rhombus = sqrt [ (D1/2)^2 + (D2/2)^2]

=> 20^2 = ( 24/2)^2 + (D2/2)^2

=> 400 - 144 = (D2/2)^2

=> 256 = (D2/2)^2

=> 16 = D2 / 2

=> D2 = 32 cm

Area = 1/2 D1 × D2

= 32 × 24 / 2

= 32 × 12

= 384 cm^2

Answer 2

Answer:

A = 384cm²

a = Side = 20cm

p = Diagonal = 24 cm

a = pq / 2

a = p² + q² / 2

a = 1 / 2 p √4² - p²

= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³