Math, asked by Davidlivinstone, 1 year ago

find area of a right triangle whose base is 1.2 M and hypotenuse 3.7 m

Answers

Answered by usp488
202
We need to find the height of this triangle at first...
So, we use the Pythagoras Theorem
Hypotenuse^2 = Base^2 + Height^2
(3.7)^2 = (1.2)^2 + Height^2
13.69 = 1.44 + heigh^2
height^2 = 13.69 - 1.44
height = √12.25 = 3.5m
Now we can find the area of this Right Angled Triangle = 1/2*h×b
1/2*3.5×1.2 = 4.2/2 = 2.1
So, Area of this Right Angled Triangle = 2.1m^2

Thankyou


jijoamal: in area of triangle how do you get 3.5 there
Answered by Ankit1408
134
hello users ...

solution:-
we know that:
Area of right angle triangle = 1/2 * Base * perpendicular height
And
According to Pythagoras theorem 
(Hypotenuse)²  = (Base)² + (perpendicular)² 

Here,
Base = 1.2 m 
Hypotenuse = 3.7 m 

=> Perpendicular = √(H² - B²)

= √ (3.7² - 1.2²)
= √ (13.69 - 1.44)
= √ 12.25
= 3.5 m 

Now,
=> Area  = 1/2 * B * P 

= 1/2 * 1.2 * 3.5 

= 1/2 * 4.2 

= 2.1 m² Answer

# hope it helps :)
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