Question

Find area of a triangle in which two sides are 8cm and 11cm and perimeter is 32cm. a. 8cm2 b. 30√8 cm2 c. √30 cm2 d. 8√30 cm2 I'm​

Answer 1

Given :

• two sides are 8cm and 11cm and perimeter is 32cm

To find :

• Find area of a triangle

Solution :

Since,

a = 8 cm,

b = 11 cm

Perimeter = 32 cm

So,

c = 32 - (8 + 11)

= 13 cm

s = 16

Area of given triangle

= √16 (16 - 8) (16 - 11) (16 - 13)

= 8√30 cm²

∴ Option d is correct option

Extra information :

• Volume of cylinder = πr²h

• T.S.A of cylinder = 2πrh + 2πr²

• Volume of cone = ⅓ πr²h

• C.S.A of cone = πrl

• T.S.A of cone = πrl + πr²

• Volume of cuboid = l × b × h

• T.S.A of cuboid = 2(lb + bh + lh)

Answer 2

$\huge \bf \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}$

$\bf \pink{GIVEN:-}$

→ suppose there is a triangle of sides 'a' , 'b' and 'c'

→ side 'a' = 8 cm

→ side 'b' = 11 cm

→ perimeter = 32 cm

$\bf { solution - }$

→ Perimeter of triangle = a + b + c

→ 32 = 8 + 11 + c

→ 32 = 19 + c

→ c = 32 - 19

→ c = 13 cm

♦ we have to find the area

★ let's find S

→ S = 32/2 = 16

→ Now , apply heron's formula

→ √s ( s - a ) ( s - b ) ( s - c )

→ √16 ( 16 - 8) ( 16 - 11 ) ( 16 - 13)

→ √16 ( 8 ) ( 5 ) ( 3 )

→ √16 (120)

→ √1920

→ 8√30 cm²

$\bf { \implies \: area \: = \: 8 \sqrt{30} cm^2}$