Question

find area of a triangle two sides of which are 10 cm and 5 cm and perimeter is 20 CM

Answer 1

Answer:

Step-by-step explanation:

side 1-10

Side2-5

Perimeter-20cm

P=s+s+s

P=10+5+s

20=15+s

20-15=s

5=s

Side3=5

Area = 1/2 *base*height

Solve further

Because i don’t have the figure

Answer 2

Answer:

Area of ∆= 1/2 b x h

Perimetre of a ∆ = side + side + side

Let third side = x

10 + 5 + x = 20

15 + x = 20

x = 20 - 15

x = 5

Third side = 5 cm

Area of ∆ = 10 x 5 x 1/2

= 50 x 1/2

= 25 cm^2

Hope it helps