find area of a triangle whose altitude are 10cm, 12cm and 15cm
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Step-by-step explanation:
Hi!
Here you go:-
Ratio of altitudes : 10:12:15.
Since Area of Triangle = (1/2) x Base x Height -(1)
For a given area the height and the base are inversely proportional.
Thus, ratio of bases => (1/10): (1/12):(1/15)
Multiplying throughout by the LCM = 60,
The ratio of sides => 6:5:4.
OR the sides would be 6a, 5a and 4a cms respectively and their corresponding altitude will be 10,12 and 15 cms respectively.
Now, from 1, Area of triangle = (1/2) x 6a x 10
Also, Area = Inradius x Semiperimter = (r) x (6a+5a+4a)/2.
Equating the two,
30a = (15a/2) x r
OR r = 4 cm.
Hence, area of incircle = pi x (r^2) = 3.14 x (4^2) = 3.14 x 16 = 50.24 cm^2.
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