Question

✍️Find area of ∆ ABC in which AB = AC = 4 cm and angle A = 90° .


⭐Note :--
Only relevant and quality answer needed .​​

Answer 1

Step-by-step explanation:

since the angle A is 90°

therefore, AB and AC are base and perpendicular respectively

area of triangle= 1/2×base×height

=1/2×4×4

=8cm²

Answer 2

Answer:

$\huge\bold\blue{αɳʂɯҽɾ}$

Given,

AC=AB=4cm and ∠A=90

we know,,

ᴀʀᴇᴀ ᴏғ ᴛʀɪᴀɴɢʟᴇ ᴀʙᴄ =

$\frac{1}{2} \times ab \times ac \\ \ \\ \frac{1}{2} \times4 \times 4 \\ \\ 8sq.cm$