find area of an irregular polygon field whose measures area as given
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Step-by-step explanation:
There are three triangles comprising the pentagon
& area of triangle by heron's formula =
s(s−a)(s−b)(s−c)
△
1
a = b = 8 , c = 12
S=
2
8+8+12
=14
△
1
=
14(6)(6)(2)
=6×2
7
△
2
a = b = 12, b = 10
S = 17
△
2
17(5)(5)(7)
=5
119
△
3
a = 10, b = 10, c = 12
S = 16
△
3
=
16(6)(6)(4)
=6×4×2=48
⇒ Total area =48+12
7
+5
119
m
2
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To find the area of an irregular polygon you must first separate the shape into regular polygons, or plane shapes. You then use the regular polygon area formulas to find the area of each of those polygons. The last step is to add all those areas together to get the total area of the irregular polygon.
Let's look at some formulas for finding the area of polygons. Remember that:
b = base
h = height
a = length of a side
w = width
Area of a triangle = 1/2 x b x h
Area of a square = a2
Area of a rectangle = w x h
Area of a parallelogram = b x h
Let's look at some formulas for finding the area of polygons. Remember that:
b = base
h = height
a = length of a side
w = width
Area of a triangle = 1/2 x b x h
Area of a square = a2
Area of a rectangle = w x h
Area of a parallelogram = b x h
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