Question

find area of an isosceles triangle with base 6 and measure of each equal side is 5 cm.​

Answer 1

Answer:

Step-by-step explanation:

Using the formulas

A=bhb

2

hb=a2﹣b2

4

Solving forA

A=1

4b4a2﹣b2=1

4·6·4·52﹣62=12

Answer 2

Answer:

12cm²

Step-by-step explanation:

Given,

Lengths of equal sides are 5cm.

Base=6cm.

Now area of isosceles triangle=1/4b√4a²-b²

=1/4(6)√4(5)²-6²

=1/2×3√4(25)-36

=1/2×3√100-36

=1/2×3√64

=1/2×3×8

=1/2×24

=12cm²

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