Question

find area of cardboard required to prepare a closed box of dimension 12 CM x 10 cm x 8 cm

Answer 1

given dimensions of the box = 12cm (length) × 10cm (breadth) × 8cm (height)

since it's a closed box, we have to find it's TSA.

TSA of the box = 2 ( lb + lh + bh )

= 2 ( 12 × 10 + 12 × 8 + 10 × 8 )

= 2 ( 120 + 96 + 80 )

= 2 × 296

= 592cm²

hence, 592cm² of cardboard is required to make the closed box.

Answer 2

Answer:

$\huge{\pink{\green{\sf{\therefore Required\:sheet=592cm^{2}}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about a piece of cardboard which was folded and make a cuboid closed box whose dimension is given.

• We have to find T.S.A of Cuboid.

$\underline \bold{Given : } \\ \implies Length = 12 \: cm \\ \implies Breadth = 10 \: cm \\ \implies Height = 8 \: cm \\ \\ \underline \bold{to \: find : } \\ \implies T.S.A \: of \: Cuboid = ?$

• We know the formula for finding Total surface area of cuboid.

$\implies T.S.A \:of \: Cuboid= 2(lb + bh + hl) \\ \implies T.S.A = 2(12 \times 10 + 10 \times 8 + 8 \times 12) \\ \implies T.S.A = 2(120 + 80 + 96) \\ \implies T.S.A = 2(296) \\ \bold{\implies T.S.A = 592{cm}^{2} }$