Find area of equilateral triangle having height of 8√3
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Answer:
64√3 cm²
Step-by-step explanation:
√3/2 × a = 8√3
√3 cancel on both sides
= a/2 = 8
a = 16 cm
Area of equilateral triangle = √3/4 a²
= √3/4 × 16 × 16
= 64√3 cm²
Answered by
0
Answer:
64√3 cm²
Step-by-step explanation:
In ΔABC, AD is the height which is 8√3 cm.
We know that in an equilateral triangle all angles are 60°, and height, median and altitude bisect the base perpendicularly.
Consider ΔADC,
Tan C = AD/DC
Tan 60° = AD/DC
√3 = 8√3 / x (Let DC be 'x')
x = 8√3 / √3
DC = x = 8 cm
DC + BD =8 + 8 = 16 cm
Area of equilateral triangle = √3/4 a²
= √3/4 × 16 × 16
= 64√3 cm²
Hence, area of equilateral triangle having height of 8√3 cm is 64√3 cm².
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