Question

Find area of isosceles triangle whose base is 10cm greater than its equal side and perimeter is 100cm

Answer 1

$\mathsf{\huge{Question}}$

 

Find the area of isosceles triangle whose base is 10cm greater than it's equal sides and perimeter is 100cm.

Find the area of isosceles triangle whose base is 10cm greater than it's equal sides and perimeter is 100cm.

$\mathsf{\huge{Answer}}$

Let x be the unknown equal sides.

So, breadth = x + 10cm.

Given that,

Perimeter = 100cm

To find,

The value of x = ?

As we know,

Perimeter is the sum of all the sides of the triangle.

Therefore, side a + side b + side c = perimeter

As it is a isosceles triangle,

Therefore, x + x + 10 + x = 100cm

3x + 10 = 100cm

3x = 100 - 10

3x = 90

x = 30

By substituting the value of x,

Therefore,

Side a = x = 30cm

 Side b = x = 30cm

Side c = x + 10 = 30 + 10 = 40cm

$\mathsf{\huge{Verification}}$

Side a + side b + side c = perimeter

30cm + 30cm + 40cm = 100cm

Therefore, the length of equal sides is 30cm and base is 40cm.