Find area of isosceles triangle whose equal sides are in the ratio 3:2 and perimeter is 32
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let the sides of triangle be 3x,3x and 2x then perimeter is 8x=32
⇒x=4
sides are 12,12 and 8
area by Heron formula is √16*4*4*8=32√2
⇒x=4
sides are 12,12 and 8
area by Heron formula is √16*4*4*8=32√2
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