find area of isosceles triangle whose perimeter is 11cm and base 5cm
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perimeter is 11cm and base 5cm
so, first side = second side = x
first side + second side + base = 11
x+x+5=11
2x + 5 = 11
2x = 11-5 = 6
x= 6/2
x= 3
S = 11/2
area = √s(s-a) (s-b) (s-c) = √(275/6)= (55√11)/4
so, first side = second side = x
first side + second side + base = 11
x+x+5=11
2x + 5 = 11
2x = 11-5 = 6
x= 6/2
x= 3
S = 11/2
area = √s(s-a) (s-b) (s-c) = √(275/6)= (55√11)/4
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