find area of polygon
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57 square cm for the given problem
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Given,
Polygon is Pentagon PQRST
It is made up of 2 shapes(Trapezium and Triangle)
Area of polygon=Area of Trapezium+Area of Triangle
First,
Area of TrapeziumPRST=½TU(TS+PR)
=½×4(6+10)
=2×16
=32sq.cm
Then,
Area of TrianglePRQ=½×PR×QV
=½×10×5
=5×5
=25sq.cm
Therefore,
Area of polygonPQRST=32sq.cm
+25sq.cm
=57sq.cm
Hence,
Area of polygonPQRST=57sq.cm
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