Question

Find area of quadrant of a circle whose radius is 3.5 cm. (use π =22/7)

Answer 1

We are given that radius of the quadrant =3.5cm

∴ Area of the quadrant AOBCA

=

4

1

πr

2

=

4

1

×

7

22

×(3.5)

2

=9.625cm

2

Area of the triangle AOD

=

2

1

×base×height

=

2

1

×OA×OD

=

2

1

×3.5×2cm

2

=3.5cm

2

Hence Area of the shaded region =Area of the quadrant-Area of the triangle AOD

=9.625−3.5

=6.125cm

2

Answer 2

Step-by-step explanation:

$area \: of \: quadrant \: of \: a \: circle \\ = \frac{1}{4} \pi \times {r}^{2} \\ = \frac{1}{4} \times \frac{22}{7} \times 3.5 \\ = \frac{11}{4} \\ = 2.75 \: c {m}^{2}$