Question

find area of quadrilateral ABCD ​

Answer 1

Step-by-step explanation:

FORMULA IS

AREA = 1/2 × DIAGONAL LENGTH × SUM OF LENGTH OF PERPENDICULAR DRAWN.

1/2×62×20=620cm(ans)

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Answer 2

Answer:

1106 cm²

Step-by-step explanation:

In ∆ADC,

∠ADC = 90° (given)

So, Base of ∆ADC = 54 cm and height = 18 cm.

So, Area of ∆ADC

= 1/2×Base×Height

= 1/2×54×18

= 486 cm²

In ∆ABC,

∠AEB = 90° (given)

So, Base of ∆ABC = 62 cm and height = 20 cm.

So, Area of ∆ABC

= 1/2×Base×Height

= 1/2×62×20

= 620 cm²

Here, ar(ABCD) = ar(ADC)+ar(ABC)

ar(ABCD) = (486+620) cm²

ar(ABCD) = 1106 cm²