find area of rectangular plot whose side is 48m and diagonal is50m
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Answered by
3
Heya !!!!
This is the solution of your query.......
Given :-
Length of one side = 48 m.
and, the length of diagonal = 50 m.
If we think of a rectangle,,,,,,,
It forms a triangle of 90° by one diagonal, length and breadth.
Length of diagonal and one side is given .....
So, we will use Pythagoras theorem :---
Diagonal ² = Length² + Breadth ².
50² = 48 ² + Breadth²
Breadth² = 50² - 48²
Breadth² = 2500 - 2304
Breadth² = 196
Breadth= 14 m.
Hence, the breadth of rectangle is 14 m.
Now, using rectangle formula.....
Area = Length × Breadth
= 48 × 14
= 672 m²
Hence, the area of rectangle is 672 m².
Hope you got the answer.....
If any doubt, feel free to ask.....
This is the solution of your query.......
Given :-
Length of one side = 48 m.
and, the length of diagonal = 50 m.
If we think of a rectangle,,,,,,,
It forms a triangle of 90° by one diagonal, length and breadth.
Length of diagonal and one side is given .....
So, we will use Pythagoras theorem :---
Diagonal ² = Length² + Breadth ².
50² = 48 ² + Breadth²
Breadth² = 50² - 48²
Breadth² = 2500 - 2304
Breadth² = 196
Breadth= 14 m.
Hence, the breadth of rectangle is 14 m.
Now, using rectangle formula.....
Area = Length × Breadth
= 48 × 14
= 672 m²
Hence, the area of rectangle is 672 m².
Hope you got the answer.....
If any doubt, feel free to ask.....
Answered by
1
let the two adjacent sides of the rectangle be -
breadth = b m
length of the plot = 48 m
now
diagonal,d = 50m
d^2 = 50 x 50
48^2 + b^2 = 2500
2304 + b^2 = 2500
b^2 = 2500-2304
b^2 = 196
b = 14
area of the plot = 48 x 14 = 672 m^2
=======================================================
hope it helps
thank you :)
breadth = b m
length of the plot = 48 m
now
diagonal,d = 50m
d^2 = 50 x 50
48^2 + b^2 = 2500
2304 + b^2 = 2500
b^2 = 2500-2304
b^2 = 196
b = 14
area of the plot = 48 x 14 = 672 m^2
=======================================================
hope it helps
thank you :)
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