find area of region embedded by y^2=16x+7 and y=x^3 +1
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Answer:
Given that:
Parabola y
2
=16x
at x=4, we have
y=±8
Hence,
Parabola and line intersect at points (4,8) and (4,−8).
Parabola has a vertex (0,0).
y
2
=16x
⇒x=
16
y
2 please mark me brainliest answer
⇒4−
16
y
2
=0
Area =∫
−8
8
(4−
16
y
2
)dy
⇒[4y−
16×3
y
3
]
−8
8
⇒[32−
8×6
8×8×8
]−[−32−
8×6
(−8)
3
]
⇒
3
128
.
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