Question

Find, area of region enclosed by parabola y=2-x^2
and the line y=-x.​

Answer 1

Answer:

finding intersection point

2-x^2=-x

x=2,-1

So integrating from -1 to2

area=$\int\limits^2_-{2-x^2+x} \, dx$

area =2x-x^3/3+x^2/2(from -1 to 2)

area=6-8/3+3/2-1/3=9/2