Math, asked by dhruvgoyal12, 11 months ago

find area of regular hexagon whose one side is 4 units​

Answers

Answered by GEETANSH02163
7

Answer:

plz mark as brainliest if helpful

Step-by-step explanation:

A regular hexagon is composed of six equilateral triangle.

Area of equilateral triangle = √3/4a²

Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.

Hence area of given regular hexagon

= 6 × √3/4 × 4²

=> 6 × √3/4 × 16

=> 6 × √3 × 4

=> 24√3 square unit

In decimals = 41.57 sq. unit (approx)

Hope it helps dear friend ☺️

Answered by Ramyasahithi
4

Answer:

41.57

Step-by-step explanation:

Area of regular hexagon=(3√3÷2)×(side)²

                                        =(3√3÷2)×4²

                                        =(3√3÷2)×16

                                        =3√3×8

                                        =24√3

                                        =41.57

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