find area of regular hexagon whose one side is 4 units
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Answered by
7
Answer:
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Step-by-step explanation:
A regular hexagon is composed of six equilateral triangle.
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 6 × √3/4 × 4²
=> 6 × √3/4 × 16
=> 6 × √3 × 4
=> 24√3 square unit
In decimals = 41.57 sq. unit (approx)
Hope it helps dear friend ☺️
Answered by
4
Answer:
41.57
Step-by-step explanation:
Area of regular hexagon=(3√3÷2)×(side)²
=(3√3÷2)×4²
=(3√3÷2)×16
=3√3×8
=24√3
=41.57
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