Question

Find area of rhombus each side is measure 20cm and one of whose diagonal is 24 cm

Answer 1

diagonal= √4a²-24²
                =√4×20²-24²
                  =√1600-576
                  =√1024
                  =32

     area =pq/2               (p and q are diagonals)
              =32×24÷2
              =384 Sq.cm

Answer 2

Hey there!

Consider ABCD to be the required rhombus ,

BD = 24 cm.
AB= BC = CD = DA = 20 cm.
Now, we need

CO= 1/2CA

Now, Consider triangle COD,
In this triangle, we know that

CD = 20 cm.
DO = 12cm

Now , This is a right angled triangle.
Accordance to Pythagoras theorem,

CD² = DO² + CO²
20² = 12² + CO²
400-144 = CO²
CO = √256 = 16cm .

2CO = AC

AC = 2(16) = 32cm .

Now,
We have another diagonal = 32cm .

Finally, We have two diagonals 32 cm, 24cm

Area of Rhombus = 1/2d*D = 1/2 * (32)(24)
= 16 * 24
= 384 cm²