Question

find area of rhombus if the measure of each side is 26cm and one diagonal 48cm in a very easy way pls​

Answer 1

A=pq

2

a=p2+q2

2

Solving forA

A=1

2p4a2﹣p2=1

2·48·4·262﹣482=480cm²

Answer 2

Step-by-step explanation:

Diagonals bisect each other at 90°

d1/2=24 cm

(d1/2)^2+(d2/2)^2=s^2

24^2+(d2/2)^2=26^2

576+(d2/2)^2=676

(d2/2)^2=100

d2/2=10

d2=20 cm

d1=48 cm

Area=1/2(d1)(d2)

= 1/2(20)(48)

= 480 cm^2