Question

find area of rhombus if the vertices are (3,0), (4,5), (-1,4) and (-2,1) taken in order​

Answer 1

Answer:

here is ur answer

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let A(3, 0), B (4, 5), C( – 1, 4) and D ( – 2, – 1) are the vertices of a rhombus ABCD.

Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2

Therefore, distance between A (3, 0) and C (- 1, 4) is given by

Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2

= √(16 + 16)

= 4√2

The distance between B (4, 5) and D (- 2, - 1) is given by

Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2

= √(36 + 36)

= 6√2

Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD

Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units

= 24 square units