Find area of rhombus perimeter is 80cm one of whose diagonal is 24m
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Answer:
384 sq. cm
Step-by-step explanation:
Rhombus perimeter : 4x side
. 80 = 4 x side
' 80/4 = side
. side =20 cm.
area of rhombus = diagonal x diagonal / 2
i.e 24 x diagonal /2
if we find the second diagonal i.e. 32 by pythagoras theorem
we get area as 24 x 32 /2
i.e. 24 x 16 = 384 cm²
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