find area of Rhombus whose one side measures 5 cm and one diagonal at 8 cm
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By Pythagoras theoreme
5^2=x^2+4^2
x^2=9
x=3
Area of a rhombus=1/2×d1×d2
1/2×6×8=24
5^2=x^2+4^2
x^2=9
x=3
Area of a rhombus=1/2×d1×d2
1/2×6×8=24
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