Find area of right angle whose hypotenuse has length 17cm and length of base is 15cm.
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.............................60cm^2
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Here length of base(b)=15cm
length of hypotenuse (h) =17cm
by using Pythagoras theorem
perpendicular =√(17^2-15^2)
=√(289-225)
=√64=8cm
now area of the triangle =1/2*b*p
=1/2*15*8
=60cm^2
...............
length of hypotenuse (h) =17cm
by using Pythagoras theorem
perpendicular =√(17^2-15^2)
=√(289-225)
=√64=8cm
now area of the triangle =1/2*b*p
=1/2*15*8
=60cm^2
...............
imnotahero:
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