find area of the minor segment of a circle of radius 28cm ,if the length of the corresponding arc APB is 44 cm
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Answered by
11
Radius = 28cm
Length of Arc APB = 2πrtheta/360
44 = 2×22/7×28×theta/360
Theta = 90°
Therefore,
area of minor segment = πr²theta/360-1/2r²sintheta.
= 22/7×28×28×90/360-1/2×28×28×sin90°. [sin90° = 1]
SOLVE THIS YOU WILL GET YOUR ANSWER..
Length of Arc APB = 2πrtheta/360
44 = 2×22/7×28×theta/360
Theta = 90°
Therefore,
area of minor segment = πr²theta/360-1/2r²sintheta.
= 22/7×28×28×90/360-1/2×28×28×sin90°. [sin90° = 1]
SOLVE THIS YOU WILL GET YOUR ANSWER..
Answered by
5
given
radius, r= 28
minor arc length ,l=44
angle will be = l/r= 44/28
area=44×180×28×28/360
formula is.. theta/ 360 × 1 × (r)²
by solving
we get area is
17248
hope u understand!!!
radius, r= 28
minor arc length ,l=44
angle will be = l/r= 44/28
area=44×180×28×28/360
formula is.. theta/ 360 × 1 × (r)²
by solving
we get area is
17248
hope u understand!!!
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