Find area of the shaded region if abcd is a square of side 28cm and apd and bpc are semicircles in a square
Answers
area of the shaded region if abcd is a square of side 28cm and apd and bpc are semicircles in a square is 20.57 cm^2
In the given figure, yellow colored portion represents the shaded portion.
- Area of shaded portion = Area of square - Area of semicircles
- = a^2 - [2 * π r^2/2]
- where,
- a is the side of a square
- "a" is the diameter of semicircle
- ∴ r = a/2 is the radius of semicircle.
- r = 28/2 = 16 cm
- given, a = 28 cm
- = 28^2 - [ 2 * π 16^2/2 ]
- = 784 - [ 256 π ]
- = 784 - [ 256 * 22/7]
- = 784 - 804.57
- = | - 20.57 |
- = 20.57 cm^2
Answer:
The Area of shaded portion is 168.56 sq cm .
Step-by-step explanation:
Given as :
ABCD is the square , each side of square = 28 cm
i.e AB = BC = CD = DA = 28 cm
APD and BPC is the semi-circle
Now, Area of square ABCD = side × side
Area of square ABCD = 28 cm × 28 cm
Or , Area of square ABCD = 784 sq cm
Again
The diameter of semi-circle = AD = 28 cm
So, the radius of semi-circle APD =
Or, r =
∴ r = 14 cm
So, Area of semi-circle = π ×
Or. Area = 3.14 ×
or, Area = 3.14 × 98 = Area = 307.72 sq cm
So, The Area of semicircle with radius r = 307.72 sq cm
Again
The diameter of semi-circle = BC = 28 cm
So, the radius of semi-circle BPD =
Or, r' =
∴ r' = 14 cm
So, Area of semi-circle = π ×
Or. Area = 3.14 ×
or, Area = 3.14 × 98 = Area = 307.72 sq cm
So, The Area of semicircle with radius r' = 307.72 sq cm
Total Area of semicircle APD and BPC = 307.72 sq cm + 307.72 sq cm
∴ Total Area of semicircle APD and BPC = 615.44 sq cm
Now,
Area of shaded portion = Area of square ABCD - Total Area of semicircle APD and BPC
i.e Area of shaded portion = 784 sq cm - 615.44 sq cm
So, Area of shaded portion = 168.56 sq cm
Hence, The Area of shaded portion is 168.56 sq cm . Answer