Question

find area of the triangle of its perimeter is 32 cm if length of its two sides is 8 cm and 11 cm
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Answer 1

Answer:

Step-by-step explanation:

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle =  

s(s−a)(s−b)(s−c)

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=  

16×8×5×3

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=8  

30

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 cm  

2