Question

Find area of the triangle whose sides measure 20 30 and 40

Answer 1

Answer: 290.47 $cm^{2}$

Step-by-step explanation:

Using Heron's formula,

Area of triangle=√s(s-a)(s-b)(s-c)

Sides = 20, 30, 40

s= a+b+c/2

20+30+40/2

=90/2 = 45

(s-a)= 45- 20 = 25

(s-b) = 45- 30 = 15

(s-c) = 45 - 40 = 5

Therefore, √(45)(25) (15) (5)

Factorizing the numbers and taking the squares out

√ $3^{2} *5^{2} * 5^{2} * 5 * 3$

= 75 × 3.8729

= 290.47 cm²

Hope this helps...