Question

find area of this triangle of side 5cm,5cm,1cm using Heron's formula

Answer 1

$\sqrt{6.1875}$

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=2.34\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle = 5 cm,5 cm,1 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{5+ 5+ 1}{2} \\ \\ : \implies s = \frac{11}{2} \\ \\ \green{ : \implies s = 5.5} \\ \\ \circ\: \bold{area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{5.5(5.5 - 5)(5.5- 5)(5 - 1)} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{5.5 \times 0.5 \times 0.5\times 4} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{5.5} \\ \\ : \implies \text{Area \: of \: triangle =}2.34 \: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle = 2.34 {cm}}^{2} }$