Question

find area of trapezium where parallel sides are 6cm and 10 cm long and are 4.8cm apart

Answer 1

$\large{\boxed{\boxed{\boxed{\bold{\green{Solution : \longrightarrow}}}}}}$

Given,

Parallel sides of the trapezium = 6cm and 10cm

Distance between them (h) = 4.8cm

•°• Area of the trapezium

$\bold{ = \frac{1}{2} \times (sum \: \: of \: \: || sides \: ) \times h} \\ \\ \bold{= \frac{1}{2} \times (6 + 10) \: cm \times 4.8 \: cm }\\ \\ \bold{= \frac{1}{2} \times 16 \: cm \times 4.8 \: cm} \\ \\ \bold{ = 38.4 \: cm}$

$\large{\bold{\red{\boxed{Have \: \: a \: \: nice \: \: day.}}}}$

Answer 2

Hello mate

here's your answer

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Area of trapezium

$= > \frac{1}{2} h(a + b)$
$= > \frac{1}{2} \times 4.8 \ \times (6 + 10) \\ \\ = 2.4 \times 16 \\ \\ = > 38.4 {cm}^{2}$
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Hope it helps you