Question

find area of triangle 6cm,6cm,4cm​

Answer 1

Step-by-step explanation:

area of the triangle is 4√5.

hope you understand

Answer 2

Given:

A triangle with -

• 1st side = 6 cm
• 2nd side = 6 cm
• 3rd side = 4 cm

What To Find:

We have to find -

• The area of the given triangle.

Formula Needed:

$\boxed{\leadsto \: \bf {Area}_{ \: (Triangle)} = \sqrt{s(s-a)(s-b)(s-c)}}$

Abbreviations Used:

• s = semi-perimeter
• a = 1st side
• b = 2nd side
• c = 3rd side

Solution:

• Finding the semi-perimeter.

We know that -

$\sf \to \: s = \dfrac{a + b + c}{2}$

Substitute the values,

$\sf \to \: s = \dfrac{6+6+4}{2}$

Add the values in the numerator,

$\sf \to \: s = \dfrac{16}{2}$

Divide 16 by 2,

$\sf \to \: s = 8 \: cm$

• Finding the area.

We know that -

$\sf \to \: {Area}_{ \: (Triangle)} = \sqrt{s(s-a)(s-b)(s-c)}$

Substitute the values,

$\sf \to \: {Area}_{ \: (Triangle)} = \sqrt{8(8-6)(8-6)(8-4)}$

Solve the brackets,

$\sf \to \: {Area}_{ \: (Triangle)} = \sqrt{8 \times 2 \times 2 \times 4}$

Multiply the numbers,

$\sf \to \: {Area}_{ \: (Triangle)} = \sqrt{128}$

Find the square root of 128,

$\sf \to \: {Area}_{ \: (Triangle)} = {11.31 \: \dots }_{ \: (approx.\!)}$

Can be written as,

$\sf \to \: {Area}_{ \: (Triangle)} = 2\sqrt{8} \: cm^2$

Final Answer:

∴ Thus, the area of the triangle is 11.31 (approx.) cm² or 2√8 cm².