Question

find area of triangle a= 0.4b=55.20c=45d=41.7​

Answer 1

i) Area of Δ

=12∣∣∣∣164003111∣∣∣∣

=12|1(0−3)−0(6−4)+1(18−0)|

=12(−3−0+18)=152sq.units

(ii) Area of triangle =12∣∣∣∣2110718111∣∣∣∣

=12∣∣∣∣2110718111∣∣∣∣ (R1→R1−R2R2→R2−R3)

12(−7+54) (Expanding alongC3)

=23.5 sq.units

(iii) Area of Δ=12∣∣∣∣−23−1−32−8111∣∣∣∣

=12|−2(2+8)+3(3+1)+1(−24+2)|

=12|−20+12−22|=15sq.units

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