find area of triangle ABC whose vertices are A(1,3) B(1,0) C(3,0)
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Answer:
3
Step-by-step explanation:
Area of triangle = 1/2 {x1(y2-y3) + x2(y3-y1) + x3 (y1-y2)
=》 1/2 {1(0-0)+1(0-3)+3(3-0)}
=》 1/2 {0-3+9}
=》 1/2 {6}
=》 6/2
=》3
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