Question

find area of triangle and side of triangles are 4 ,5,,6 plz tell me​

Answer 1

Answer:

hope this is helpful..

pls make me brainlist..

thanku, saranghae

Answer 2

Question:

find area of triangle and side of triangles are 4 ,5,6  

Given:

In ΔABC

• AB = 4 cm

• BC =  5 cm

• CA = 6cm

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){ \bf A }\put(0.5,-0.3){ \bf C }\put(5.2,-0.3){ \bf B }\end{picture}$

To find:

• Area of the triangle

Formula used:

$\sqrt{s(s-a)(s-b)(s-c)}$

Where s = semi perimeter

$s=\frac{a+b+c}{2}$

Solution:

In ΔABC

• AB = 4 cm

• BC =  5 cm

• CA = 6cm

By herons formula

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

Where s = semi perimeter

$s=\frac{a+b+c}{2}$

$s=\frac{4+5+6}{2}$

$s=\frac{15}{2}$

$s = 7.5$

$\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{7.5(7.5-4)(7.5-5)(7.5-6)}$

$\sqrt{7.5(3.5)(2.5)(1.5)}$

$\sqrt{98.4375}$

$=9.92156741649$

Answer:

$\sqrt{98.4375}$

$\frac{15}{4}\sqrt{7} cm$