Question

find area of triangle if its side are 7cm,8cm,5cm​

Answer 1

Answer:

17.32 cm² This is the Answer

Answer 2

Answer:

Answer:Area of the Traingle:-

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$Theorem K's Formula:-

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$Theorem K's Formula:-√s[(s-a)(s-b)(s-c)]

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$Theorem K's Formula:-√s[(s-a)(s-b)(s-c)]$\sqrt{10(10 - 7)(10 - 8)(10 - 5)} \\ \sqrt{10 \times 3 \times 2 \times 5} \\ \sqrt{300} \\ 17.32$

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$Theorem K's Formula:-√s[(s-a)(s-b)(s-c)]$\sqrt{10(10 - 7)(10 - 8)(10 - 5)} \\ \sqrt{10 \times 3 \times 2 \times 5} \\ \sqrt{300} \\ 17.32$Hope it helps :)

Answer:Area of the Traingle:-$s = \frac{1}{2}(7 + 8 + 5) \\ \frac{1}{2} \times 20 \\ 10$Theorem K's Formula:-√s[(s-a)(s-b)(s-c)]$\sqrt{10(10 - 7)(10 - 8)(10 - 5)} \\ \sqrt{10 \times 3 \times 2 \times 5} \\ \sqrt{300} \\ 17.32$Hope it helps :)