Question

find area of triangle two sides of which are 18 cm,10 cm and perimeter is 42 cm​

Answer 1

Answer:

Step-by-step explanation:

ANSWER

Let the sides of the triangle be a=18 cm,b=10 cm

Perimeter (2s) =42 cm

s=  

2

42

​  

=21 cm

c=42−(18+10) cm=14 cm

Area of triangle =  

s(s−a)(s−b)(s−c)

​  

 

=  

21(21−18)(21−10)(21−14)

​  

 

=21  

11

​  

 cm  

2

 

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Answer 2

Answer:

may be this is your answer