find area of triangle two sides of which are 18 cm,10 cm and perimeter is 42 cm
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Let the sides of the triangle be a=18 cm,b=10 cm
Perimeter (2s) =42 cm
s=
2
42
=21 cm
c=42−(18+10) cm=14 cm
Area of triangle =
s(s−a)(s−b)(s−c)
=
21(21−18)(21−10)(21−14)
=21
11
cm
2
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