Question

find area of triangle which two side is 8 cm and 11​

Answer 1

Answer:

Answer

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle =

s(s−a)(s−b)(s−c)

=

16×8×5×3

=8

30

cm

2